2x^2+10x-2100=0

Solution for 2x^2+10x-2100=0 equation:

2x^2+10x-2100=0

a = 2; b = 10; c = -2100;
Δ = b2-4ac
Δ = 102-4·2·(-2100)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-130}{2*2}=\frac{-140}{4}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+130}{2*2}=\frac{120}{4}
=30
$